- original principal
- nominal interest rate
- interest period or conversion period
- frequency of conversions
- periodic interest rate
- number of interest periods in the investment period
S=P(1+i)n
I=S-P
consider the following examples:
Find the future value of RM1000which was investsed for
a)4 years at 4% compounded annually
b)2 years 3 months at 4% compounded quarterly
c)5 years 6 months at 14% compounded semi-annually
solution:
a)S=1000(1+(4%/1))4 =RM1169.86
b)S=1000(1+(4%/4)9 =RM1093.69
c)S=1000(1+(14%/2)11=RM2104.85
Woaa...I found out that this chapter is quite difficult..I hope that I will understand it even it is confusing huhuhu...
1 comment:
nice blog...
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